What are the solutions to the equation 0=6x^2+6x-12 ?

The solutions to the equation 0=6x^2+6x-12 are x=1,x=-2

Find the zeros of 0=6x^2+6x-12

The zeros of 0=6x^2+6x-12 are x=1,x=-2

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0 = 6 x^{2} + 6 x - 12

x = 1, x = - 2

Solution steps

0 = 6 x^{2} + 6 x - 12

Switch sides

6 x^{2} + 6 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 12) = 18

x_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 18}{2 \cdot 6}, x_{2} = \frac{- 6 - 18}{2 \cdot 6}

x = \frac{- 6 + 18}{2 \cdot 6} : 1

x = \frac{- 6 - 18}{2 \cdot 6} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

\frac{2 x - 3}{x + 1} < 1

8 2^{2}

- x^{2} + 7 x + 11 = 0

(9 + 4 i)^{2}

19 \cdot 2

What are the solutions to the equation 0=6x^2+6x-12 ?
The solutions to the equation 0=6x^2+6x-12 are x=1,x=-2
Find the zeros of 0=6x^2+6x-12
The zeros of 0=6x^2+6x-12 are x=1,x=-2