What are the solutions to the equation (y^2)/2 =2y ?

The solutions to the equation (y^2)/2 =2y are y=4,y=0

Find the zeros of (y^2)/2 =2y

The zeros of (y^2)/2 =2y are y=4,y=0

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\frac{y ^{2}}{2} = 2 y

y = 4, y = 0

Solution steps

\frac{y ^{2}}{2} = 2 y

Multiply both sides by

2

y^{2} = 4 y

Move

4 y

to the left side

y^{2} - 4 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

y_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, y_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

y = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

y = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 4, y = 0

2 x + 12 \leq 20

\frac{11}{2} - \frac{1}{2}

4 x + 6 \geq - 10 or 8 x + 4 \geq - 12

(b^{2} + 3 b) + b + 3 = 0

- 3 x^{2} y^{5} (5 x^{5} y^{4})

What are the solutions to the equation (y^2)/2 =2y ?
The solutions to the equation (y^2)/2 =2y are y=4,y=0
Find the zeros of (y^2)/2 =2y
The zeros of (y^2)/2 =2y are y=4,y=0