What is 4x+6>=-10\lor 8x+4>=-12 ?

The solution to 4x+6>=-10\lor 8x+4>=-12 is x>=-4

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4x+6>=-10\lor 8x+4>=-12

4 x + 6 \geq - 10 or 8 x + 4 \geq - 12

x \geq - 4

Solution steps

4 x + 6 \geq - 10 or 8 x + 4 \geq - 12

4 x + 6 \geq - 10 : x \geq - 4

8 x + 4 \geq - 12 : x \geq - 2

Combine the intervals

x \geq - 4 or x \geq - 2

Merge Overlapping Intervals

x \geq - 4

(b^{2} + 3 b) + b + 3 = 0

- 3 x^{2} y^{5} (5 x^{5} y^{4})

- 2 x < - 24

(- 7 + 3 i) - (2 - 6 i)

4 ∣ x - 1 ∣ - 8 \leq 40

What is 4x+6>=-10\lor 8x+4>=-12 ?
The solution to 4x+6>=-10\lor 8x+4>=-12 is x>=-4