What are the solutions to the equation -2t^2-40t=-74 ?

The solutions to the equation -2t^2-40t=-74 are t=-10-sqrt(137),t=sqrt(137)-10

Find the zeros of -2t^2-40t=-74

The zeros of -2t^2-40t=-74 are t=-10-sqrt(137),t=sqrt(137)-10

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- 2 t^{2} - 40 t = - 74

t = - 10 - 137, t = 137 - 10

Decimal Notation

t = - 21.70469 \dots, t = 1.70469 \dots

Solution steps

- 2 t^{2} - 40 t = - 74

Move

74

to the left side

- 2 t^{2} - 40 t + 74 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 ( - 2 ) \cdot 74}{2 ( - 2 )}

(- 40)^{2} - 4 (- 2) \cdot 74 = 4137

t_{1, 2} = \frac{- ( - 40 ) \pm 4 137}{2 ( - 2 )}

Separate the solutions

t_{1} = \frac{- ( - 40 ) + 4 137}{2 ( - 2 )}, t_{2} = \frac{- ( - 40 ) - 4 137}{2 ( - 2 )}

t = \frac{- ( - 40 ) + 4 137}{2 ( - 2 )} : - 10 - 137

t = \frac{- ( - 40 ) - 4 137}{2 ( - 2 )} : 137 - 10

The solutions to the quadratic equation are:

t = - 10 - 137, t = 137 - 10

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3 x^{2} + 11 x + 10

What are the solutions to the equation -2t^2-40t=-74 ?
The solutions to the equation -2t^2-40t=-74 are t=-10-sqrt(137),t=sqrt(137)-10
Find the zeros of -2t^2-40t=-74
The zeros of -2t^2-40t=-74 are t=-10-sqrt(137),t=sqrt(137)-10