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Popular >

6x^2+17x-3>= 0

Solution

6 x^{2} + 17 x - 3 \geq 0

Solution

x \leq - 3 or x \geq \frac{1}{6}

+2

Interval Notation

(- \infty, - 3] \cup [\frac{1}{6}, \infty)

Decimal Notation

x \leq - 3 or x \geq 0.16666 \dots

Solution steps

6 x^{2} + 17 x - 3 \geq 0

Factor

6 x^{2} + 17 x - 3 : (6 x - 1) (x + 3)

(6 x - 1) (x + 3) \geq 0

Identify the intervals

x \leq - 3 or x \geq \frac{1}{6}

Popular Examples

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3 x^{2} + 11 x + 10

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3m^2+13=m^2+397

3 m^{2} + 13 = m^{2} + 397

factor 2x^2y-5x^2-2y+5 factor

2 x^{2} y - 5 x^{2} - 2 y + 5

Frequently Asked Questions (FAQ)

What is 6x^2+17x-3>= 0 ?
The solution to 6x^2+17x-3>= 0 is x<=-3\lor x>= 1/6