What are the solutions to the equation -3/4 (x-1/2)^2+9=0 ?

The solutions to the equation -3/4 (x-1/2)^2+9=0 are x=2sqrt(3)+1/2 ,x=-2sqrt(3)+1/2

Find the zeros of -3/4 (x-1/2)^2+9=0

The zeros of -3/4 (x-1/2)^2+9=0 are x=2sqrt(3)+1/2 ,x=-2sqrt(3)+1/2

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- \frac{3}{4} (x - \frac{1}{2})^{2} + 9 = 0

x = 23 + \frac{1}{2}, x = - 23 + \frac{1}{2}

Decimal Notation

x = 3.96410 \dots, x = - 2.96410 \dots

Solution steps

- \frac{3}{4} (x - \frac{1}{2})^{2} + 9 = 0

Move

9

to the right side

- \frac{3}{4} (x - \frac{1}{2})^{2} = - 9

Multiply both sides by

4

- 3 (x - \frac{1}{2})^{2} = - 36

Divide both sides by

- 3

(x - \frac{1}{2})^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - \frac{1}{2} = 12 : x = 23 + \frac{1}{2}

Solve

x - \frac{1}{2} = - 12 : x = - 23 + \frac{1}{2}

The solutions to the quadratic equation are:

x = 23 + \frac{1}{2}, x = - 23 + \frac{1}{2}

12 x^{3} - 31 x^{2} + 20 x

lo g_{5} (3 x + 6 y)

- 5 = 2 x - 3

- 2 t^{2} - 40 t = - 74

(\frac{1}{3})^{2} + 3^{2}

What are the solutions to the equation -3/4 (x-1/2)^2+9=0 ?
The solutions to the equation -3/4 (x-1/2)^2+9=0 are x=2sqrt(3)+1/2 ,x=-2sqrt(3)+1/2
Find the zeros of -3/4 (x-1/2)^2+9=0
The zeros of -3/4 (x-1/2)^2+9=0 are x=2sqrt(3)+1/2 ,x=-2sqrt(3)+1/2