What are the solutions to the equation 2p^2-3p-3=0 ?

The solutions to the equation 2p^2-3p-3=0 are p=(3+sqrt(33))/4 ,p=(3-sqrt(33))/4

Find the zeros of 2p^2-3p-3=0

The zeros of 2p^2-3p-3=0 are p=(3+sqrt(33))/4 ,p=(3-sqrt(33))/4

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2 p^{2} - 3 p - 3 = 0

p = \frac{3 + 33}{4}, p = \frac{3 - 33}{4}

Decimal Notation

p = 2.18614 \dots, p = - 0.68614 \dots

Solution steps

2 p^{2} - 3 p - 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 3) = 33

p_{1, 2} = \frac{- ( - 3 ) \pm 33}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 3 ) + 33}{2 \cdot 2}, p_{2} = \frac{- ( - 3 ) - 33}{2 \cdot 2}

p = \frac{- ( - 3 ) + 33}{2 \cdot 2} : \frac{3 + 33}{4}

p = \frac{- ( - 3 ) - 33}{2 \cdot 2} : \frac{3 - 33}{4}

The solutions to the quadratic equation are:

p = \frac{3 + 33}{4}, p = \frac{3 - 33}{4}

\frac{5 ^{0.001} - 1}{0.001}

(v^{- 1})^{\frac{1}{9}}

\frac{- 7 π}{4}

1356 - x = 284

8 n \geq 7 n - 3

What are the solutions to the equation 2p^2-3p-3=0 ?
The solutions to the equation 2p^2-3p-3=0 are p=(3+sqrt(33))/4 ,p=(3-sqrt(33))/4
Find the zeros of 2p^2-3p-3=0
The zeros of 2p^2-3p-3=0 are p=(3+sqrt(33))/4 ,p=(3-sqrt(33))/4