What are the solutions to the equation 2(3x-1)^2-5=3 ?

The solutions to the equation 2(3x-1)^2-5=3 are x=1,x=-1/3

Find the zeros of 2(3x-1)^2-5=3

The zeros of 2(3x-1)^2-5=3 are x=1,x=-1/3

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2 (3 x - 1)^{2} - 5 = 3

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

2 (3 x - 1)^{2} - 5 = 3

Move

5

to the right side

2 (3 x - 1)^{2} = 8

Divide both sides by

2

(3 x - 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = 4 : x = 1

Solve

3 x - 1 = - 4 : x = - \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{3}

57 - 82 (- \frac{35}{3}) - (- \frac{35}{3})^{2}

40 - 5 x

a^{3} + a

3 s - 9 = 6

x^{2} - 53 x + 196 = 0

What are the solutions to the equation 2(3x-1)^2-5=3 ?
The solutions to the equation 2(3x-1)^2-5=3 are x=1,x=-1/3
Find the zeros of 2(3x-1)^2-5=3
The zeros of 2(3x-1)^2-5=3 are x=1,x=-1/3