What are the solutions to the equation x^2-53x+196=0 ?

The solutions to the equation x^2-53x+196=0 are x=49,x=4

Find the zeros of x^2-53x+196=0

The zeros of x^2-53x+196=0 are x=49,x=4

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x^{2} - 53 x + 196 = 0

x = 49, x = 4

Solution steps

x^{2} - 53 x + 196 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 53 ) \pm ( - 53 ) ^{2} - 4 \cdot 1 \cdot 196}{2 \cdot 1}

(- 53)^{2} - 4 \cdot 1 \cdot 196 = 45

x_{1, 2} = \frac{- ( - 53 ) \pm 45}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 53 ) + 45}{2 \cdot 1}, x_{2} = \frac{- ( - 53 ) - 45}{2 \cdot 1}

x = \frac{- ( - 53 ) + 45}{2 \cdot 1} : 49

x = \frac{- ( - 53 ) - 45}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 49, x = 4

4 x - 6 \geq 14

4 a^{2} + 21 a + 5

4 x + 21 = - 9 - 2 x

61 = - x

3 x^{2} - 15 = - 75

What are the solutions to the equation x^2-53x+196=0 ?
The solutions to the equation x^2-53x+196=0 are x=49,x=4
Find the zeros of x^2-53x+196=0
The zeros of x^2-53x+196=0 are x=49,x=4