What are the solutions to the equation x^2+24x+144=17 ?

The solutions to the equation x^2+24x+144=17 are x=-12+sqrt(17),x=-12-sqrt(17)

Find the zeros of x^2+24x+144=17

The zeros of x^2+24x+144=17 are x=-12+sqrt(17),x=-12-sqrt(17)

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x^{2} + 24 x + 144 = 17

x = - 12 + 17, x = - 12 - 17

Decimal Notation

x = - 7.87689 \dots, x = - 16.12310 \dots

Solution steps

x^{2} + 24 x + 144 = 17

Move

17

to the left side

x^{2} + 24 x + 127 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot 127}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot 127 = 217

x_{1, 2} = \frac{- 24 \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 24 + 2 17}{2 \cdot 1}, x_{2} = \frac{- 24 - 2 17}{2 \cdot 1}

x = \frac{- 24 + 2 17}{2 \cdot 1} : - 12 + 17

x = \frac{- 24 - 2 17}{2 \cdot 1} : - 12 - 17

The solutions to the quadratic equation are:

x = - 12 + 17, x = - 12 - 17

4 x^{2} - x = 0

5 x - 29 > - 34

(x + 1) (x + 3) > 0

\frac{π}{2} + π

a + a

What are the solutions to the equation x^2+24x+144=17 ?
The solutions to the equation x^2+24x+144=17 are x=-12+sqrt(17),x=-12-sqrt(17)
Find the zeros of x^2+24x+144=17
The zeros of x^2+24x+144=17 are x=-12+sqrt(17),x=-12-sqrt(17)