What are the solutions to the equation 4x^2-x=0 ?

The solutions to the equation 4x^2-x=0 are x= 1/4 ,x=0

Find the zeros of 4x^2-x=0

The zeros of 4x^2-x=0 are x= 1/4 ,x=0

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4 x^{2} - x = 0

x = \frac{1}{4}, x = 0

Decimal Notation

x = 0.25, x = 0

Solution steps

4 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 4}

x = \frac{- ( - 1 ) + 1}{2 \cdot 4} : \frac{1}{4}

x = \frac{- ( - 1 ) - 1}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 0

5 x - 29 > - 34

(x + 1) (x + 3) > 0

\frac{π}{2} + π

a + a

9 - ∣ p + 6 ∣ = 4

What are the solutions to the equation 4x^2-x=0 ?
The solutions to the equation 4x^2-x=0 are x= 1/4 ,x=0
Find the zeros of 4x^2-x=0
The zeros of 4x^2-x=0 are x= 1/4 ,x=0