What are the solutions to the equation 20.24=0.01v^2+0.7v ?

The solutions to the equation 20.24=0.01v^2+0.7v are v=22,v=-92

Find the zeros of 20.24=0.01v^2+0.7v

The zeros of 20.24=0.01v^2+0.7v are v=22,v=-92

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20.24 = 0.01 v^{2} + 0.7 v

v = 22, v = - 92

Solution steps

20.24 = 0.01 v^{2} + 0.7 v

Multiply both sides by

100

2024 = v^{2} + 70 v

Switch sides

v^{2} + 70 v = 2024

Move

2024

to the left side

v^{2} + 70 v - 2024 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 \cdot 1 \cdot ( - 2024 )}{2 \cdot 1}

7 0^{2} - 4 \cdot 1 \cdot (- 2024) = 114

v_{1, 2} = \frac{- 70 \pm 114}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 70 + 114}{2 \cdot 1}, v_{2} = \frac{- 70 - 114}{2 \cdot 1}

v = \frac{- 70 + 114}{2 \cdot 1} : 22

v = \frac{- 70 - 114}{2 \cdot 1} : - 92

The solutions to the quadratic equation are:

v = 22, v = - 92

- x^{2} + 3 x - 3 = 0

6 m^{2} - 13 am - 15 a^{2}

15 x - x^{2} = 0

(x + 3)^{2} + 25 = 0

8^{\frac{4}{3}}

What are the solutions to the equation 20.24=0.01v^2+0.7v ?
The solutions to the equation 20.24=0.01v^2+0.7v are v=22,v=-92
Find the zeros of 20.24=0.01v^2+0.7v
The zeros of 20.24=0.01v^2+0.7v are v=22,v=-92