What are the solutions to the equation 15x-x^2=0 ?

The solutions to the equation 15x-x^2=0 are x=0,x=15

Find the zeros of 15x-x^2=0

The zeros of 15x-x^2=0 are x=0,x=15

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15 x - x^{2} = 0

x = 0, x = 15

Solution steps

15 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 15 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1 5^{2} - 4 (- 1) \cdot 0 = 15

x_{1, 2} = \frac{- 15 \pm 15}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 15 + 15}{2 ( - 1 )}, x_{2} = \frac{- 15 - 15}{2 ( - 1 )}

x = \frac{- 15 + 15}{2 ( - 1 )} : 0

x = \frac{- 15 - 15}{2 ( - 1 )} : 15

The solutions to the quadratic equation are:

x = 0, x = 15

(x + 3)^{2} + 25 = 0

8^{\frac{4}{3}}

\frac{( x ^{3} + y ^{3} )}{( x - y )}

lo g_{2} (36) - 2 lo g_{2} (3)

What are the solutions to the equation 15x-x^2=0 ?
The solutions to the equation 15x-x^2=0 are x=0,x=15
Find the zeros of 15x-x^2=0
The zeros of 15x-x^2=0 are x=0,x=15