What is 6^{sqrt(x)}<= 5+6^{1-sqrt(x)} ?

The solution to 6^{sqrt(x)}<= 5+6^{1-sqrt(x)} is No Solution

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6^{sqrt(x)}<= 5+6^{1-sqrt(x)}

6^{x} \leq 5 + 6^{1 - x}

No Solution

Solution steps

6^{x} \leq 5 + 6^{1 - x}

Apply exponent rules

(6^{x})^{2} \leq 5 \cdot 6^{x} + 6

Let

u = 6^{x}

u^{2} \leq 5 u + 6

u^{2} \leq 5 u + 6 : - 1 \leq u \leq 6

- 1 \leq u \leq 6

Substitute back

u = 6^{x}

- 1 \leq 6^{x} \leq 6

a \leq u \leq b

then

a \leq u and u \leq b

- 1 \leq 6^{x} and 6^{x} \leq 6

- 1 \leq 6^{x} :

True for all

x

6^{x} \leq 6 : 0 \leq x \leq 1

Combine the intervals

No Solution and No Solution

Merge Overlapping Intervals

No Solution for x \in R

No Solution

∣ x + 8 ∣ + 9 = 7

y^{2} - 6 y + 8 = 0

2 - (\frac{1}{2})^{- 2}

∣ 7 x - 5 ∣ + 1 \geq 9

0.002 n + 15 = 2

What is 6^{sqrt(x)}<= 5+6^{1-sqrt(x)} ?
The solution to 6^{sqrt(x)}<= 5+6^{1-sqrt(x)} is No Solution