What are the solutions to the equation y^2-6y+8=0 ?

The solutions to the equation y^2-6y+8=0 are y=4,y=2

Find the zeros of y^2-6y+8=0

The zeros of y^2-6y+8=0 are y=4,y=2

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y^{2} - 6 y + 8 = 0

y = 4, y = 2

Solution steps

y^{2} - 6 y + 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

y_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

y = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

y = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

y = 4, y = 2

2 - (\frac{1}{2})^{- 2}

∣ 7 x - 5 ∣ + 1 \geq 9

0.002 n + 15 = 2

\frac{π}{5} \cdot \frac{180}{π}

\frac{- \frac{24}{25}}{- \frac{7}{25}}

What are the solutions to the equation y^2-6y+8=0 ?
The solutions to the equation y^2-6y+8=0 are y=4,y=2
Find the zeros of y^2-6y+8=0
The zeros of y^2-6y+8=0 are y=4,y=2