What are the solutions to the equation 5x^2=x-2 ?

The solutions to the equation 5x^2=x-2 are x= 1/10+i(sqrt(39))/(10),x= 1/10-i(sqrt(39))/(10)

Find the zeros of 5x^2=x-2

The zeros of 5x^2=x-2 are x= 1/10+i(sqrt(39))/(10),x= 1/10-i(sqrt(39))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} = x - 2

x = \frac{1}{10} + i \frac{39}{10}, x = \frac{1}{10} - i \frac{39}{10}

Solution steps

5 x^{2} = x - 2

Move

2

to the left side

5 x^{2} + 2 = x

Move

x

to the left side

5 x^{2} + 2 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

Simplify

(- 1)^{2} - 4 \cdot 5 \cdot 2 : 39 i

x_{1, 2} = \frac{- ( - 1 ) \pm 39 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 39 i}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 39 i}{2 \cdot 5}

x = \frac{- ( - 1 ) + 39 i}{2 \cdot 5} : \frac{1}{10} + i \frac{39}{10}

x = \frac{- ( - 1 ) - 39 i}{2 \cdot 5} : \frac{1}{10} - i \frac{39}{10}

The solutions to the quadratic equation are:

x = \frac{1}{10} + i \frac{39}{10}, x = \frac{1}{10} - i \frac{39}{10}

\frac{12 i}{3 - 3 i}

2 (5 x + 8) = 6 x + 20

\frac{( 2 + 3 i )}{( 3 + 4 i )}

\frac{p ^{- 8}}{7 ^{- 2} q ^{- 9}}

5 x^{2} + x - 6 = 0

What are the solutions to the equation 5x^2=x-2 ?
The solutions to the equation 5x^2=x-2 are x= 1/10+i(sqrt(39))/(10),x= 1/10-i(sqrt(39))/(10)
Find the zeros of 5x^2=x-2
The zeros of 5x^2=x-2 are x= 1/10+i(sqrt(39))/(10),x= 1/10-i(sqrt(39))/(10)