What is (p^{-8})/(7^{-2)q^{-9}} ?

The solution to (p^{-8})/(7^{-2)q^{-9}} is (49q^9)/(p^8)

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simplify (p^{-8})/(7^{-2)q^{-9}}

simplify

\frac{p ^{- 8}}{7 ^{- 2} q ^{- 9}}

\frac{49 q ^{9}}{p ^{8}}

Solution steps

\frac{p ^{- 8}}{7 ^{- 2} q ^{- 9}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

p^{- 8} = \frac{1}{p ^{8}}

= \frac{\frac{1}{p ^{8}}}{7 ^{- 2} q ^{- 9}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{p ^{8} \cdot 7 ^{- 2} q ^{- 9}}

Simplify

p^{8} \cdot 7^{- 2} q^{- 9} : \frac{p ^{8}}{49 q ^{9}}

= \frac{1}{\frac{p ^{8}}{49 q ^{9}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{49 q ^{9}}{p ^{8}}

5 x^{2} + x - 6 = 0

\frac{- 2}{3}

x^{2} (x - 1) \leq 0

0. 5^{2} + 0. 5^{2}

\frac{2}{3} ∣ x + 5 ∣ - \frac{5}{3} = - 1

What is (p^{-8})/(7^{-2)q^{-9}} ?
The solution to (p^{-8})/(7^{-2)q^{-9}} is (49q^9)/(p^8)