What are the solutions to the equation 2-(z-2)^2=z^2 ?

The solutions to the equation 2-(z-2)^2=z^2 are z=1

Find the zeros of 2-(z-2)^2=z^2

The zeros of 2-(z-2)^2=z^2 are z=1

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2 - (z - 2)^{2} = z^{2}

z = 1

Solution steps

2 - (z - 2)^{2} = z^{2}

Expand

2 - (z - 2)^{2} : - z^{2} + 4 z - 2

- z^{2} + 4 z - 2 = z^{2}

Move

z^{2}

to the left side

- 2 z^{2} + 4 z - 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

4^{2} - 4 (- 2) (- 2) = 0

z_{1, 2} = \frac{- 4 \pm 0}{2 ( - 2 )}

z = \frac{- 4}{2 ( - 2 )}

\frac{- 4}{2 ( - 2 )} = 1

z = 1

The solution to the quadratic equation is:

z = 1

v^{2} + 7 v + 6 = 0

a^{2} - 10 a - 24 = 0

3 d e + 6 df + 12 d g

\frac{( 4 n ) ^{2}}{- 4 n ^{- 5}}

y + 2 = 0

What are the solutions to the equation 2-(z-2)^2=z^2 ?
The solutions to the equation 2-(z-2)^2=z^2 are z=1
Find the zeros of 2-(z-2)^2=z^2
The zeros of 2-(z-2)^2=z^2 are z=1