What are the solutions to the equation v^2+7v+6=0 ?

The solutions to the equation v^2+7v+6=0 are v=-1,v=-6

Find the zeros of v^2+7v+6=0

The zeros of v^2+7v+6=0 are v=-1,v=-6

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v^{2} + 7 v + 6 = 0

v = - 1, v = - 6

Solution steps

v^{2} + 7 v + 6 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 6 = 5

v_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 7 + 5}{2 \cdot 1}, v_{2} = \frac{- 7 - 5}{2 \cdot 1}

v = \frac{- 7 + 5}{2 \cdot 1} : - 1

v = \frac{- 7 - 5}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

v = - 1, v = - 6

a^{2} - 10 a - 24 = 0

3 d e + 6 df + 12 d g

\frac{( 4 n ) ^{2}}{- 4 n ^{- 5}}

y + 2 = 0

\frac{1}{3} \times 3

What are the solutions to the equation v^2+7v+6=0 ?
The solutions to the equation v^2+7v+6=0 are v=-1,v=-6
Find the zeros of v^2+7v+6=0
The zeros of v^2+7v+6=0 are v=-1,v=-6