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受欢迎的代数 >

((-2+9i))/((-6+i)(s))=-1

解答

\frac{( - 2 + 9 i )}{( - 6 + i ) ( s )} = - 1

解答

s = - \frac{21}{37} + \frac{52}{37} i

求解步骤

\frac{( - 2 + 9 i )}{( - 6 + i ) ( s )} = - 1

替代

s = x + y i

\frac{- 2 + 9 i}{( - 6 + i ) ( x + y i )} = - 1

在两边乘以

(- 6 + i) (x + y i)

\frac{- 2 + 9 i}{( - 6 + i ) ( x + y i )} (- 6 + i) (x + y i) = - 1 \cdot (- 6 + i) (x + y i)

乘开

- 2 + 9 i = (6 x + y) + i (- x + 6 y)

复数仅在实部和虚部均相等时才相等改写为方程组:

[- 2 = 6 x + y 9 = - x + 6 y]

[- 2 = 6 x + y 9 = - x + 6 y] : x = - \frac{21}{37}, y = \frac{52}{37}

s = x + y i

代回

s = - \frac{21}{37} + \frac{52}{37} i

流行的例子

(z - i)^{2} = 2

r(t)=ti+t^2j+2tk,(2,4,4)

r (t) = t i + t^{2} j + 2 t k, (2, 4, 4)

x^{2} + x + 1 + i = 0

x+i(y+1)=2x+i2y

x + i (y + 1) = 2 x + i 2 y

v = i r, r