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Beliebt Algebra >

(x^2+2x-4)(x^2-x-32)=0

Lösung

(x^{2} + 2 x - 4) (x^{2} - x - 32) = 0

Lösung

x = - 1 + 5, x = - 1 - 5, x = \frac{1 + 129}{2}, x = \frac{1 - 129}{2}

+1

Dezimale

x = 1.23606 \dots, x = - 3.23606 \dots, x = 6.17890 \dots, x = - 5.17890 \dots

Schritte zur Lösung

(x^{2} + 2 x - 4) (x^{2} - x - 32) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x^{2} + 2 x - 4 = 0 or x^{2} - x - 32 = 0

Löse

x^{2} + 2 x - 4 = 0 : x = - 1 + 5, x = - 1 - 5

Löse

x^{2} - x - 32 = 0 : x = \frac{1 + 129}{2}, x = \frac{1 - 129}{2}

Die Lösungen sind

x = - 1 + 5, x = - 1 - 5, x = \frac{1 + 129}{2}, x = \frac{1 - 129}{2}

Graph

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