w^3=5

Lösung

w^{3} = 5

w = 35, w = - 35 \frac{1}{2} + 35 \frac{3}{2} i, w = - 35 \frac{1}{2} - 35 \frac{3}{2} i

Schritte zur Lösung

w^{3} = 5

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

w = 35, w = 35 \frac{- 1 + 3 i}{2}, w = 35 \frac{- 1 - 3 i}{2}

Vereinfache

35 \frac{- 1 + 3 i}{2} : - 35 \frac{1}{2} + 35 \frac{3}{2} i

Vereinfache

35 \frac{- 1 - 3 i}{2} : - 35 \frac{1}{2} - 35 \frac{3}{2} i

w = 35, w = - 35 \frac{1}{2} + 35 \frac{3}{2} i, w = - 35 \frac{1}{2} - 35 \frac{3}{2} i

2 x^{4} + x^{3} - 7 x^{2} - 3 x + 3 = 0

7 x^{9} = (7 x^{10}) - (7 x)

8 x^{3} = 0

0 = x^{4} - 18 x^{2} + 32

x (x - 5)^{3} - 14 (x - 5)^{2} = 0