6^x=8^{2x-1}

Lösung

6^{x} = 8^{2 x - 1}

x = \frac{3 ln ( 2 )}{ln ( \frac{32}{3} )}

Dezimale

x = 0.87846 \dots

Schritte zur Lösung

6^{x} = 8^{2 x - 1}

Wende Exponentenregel an

x ln (6) = (2 x - 1) ln (8)

Löse

x ln (6) = (2 x - 1) ln (8) : x = \frac{3 ln ( 2 )}{ln ( \frac{32}{3} )}

x = \frac{3 ln ( 2 )}{ln ( \frac{32}{3} )}

1 0^{4 x + 1} = 132

4^{x} - 6 \cdot 2^{x} - 16 = 0

ln (e^{t^{2} - t}) = 6

5 x^{3} e^{x} = 2 x e^{x}

2^{8 x + 5} = 8^{x^{2} - 2}