2^{5^{x-3}}=2^{25^x}

Lösung

2^{5^{x - 3}} = 2^{2 5^{x}}

x = - 3

Schritte zur Lösung

2^{5^{x - 3}} = 2^{2 5^{x}}

Wende Exponentenregel an

x - 3 = 2 x

Löse

x - 3 = 2 x : x = - 3

x = - 3

e^{2 x} - 4 \cdot e^{x} + 4 = 0

4^{x^{2}} - 2^{x^{2}} = 240

so l v e f or x, x y = e^{x + y}

a^{x + 3} = a^{8}

7^{x} = 10