3^{x+4}=2^{x-16}

Lösung

3^{x + 4} = 2^{x - 16}

x = \frac{- 16 ln ( 2 ) - 4 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

Dezimale

x = - 38.19022 \dots

Schritte zur Lösung

3^{x + 4} = 2^{x - 16}

Wende Exponentenregel an

(x + 4) ln (3) = (x - 16) ln (2)

Löse

(x + 4) ln (3) = (x - 16) ln (2) : x = \frac{- 16 ln ( 2 ) - 4 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{- 16 ln ( 2 ) - 4 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

so l v e f or t, 2 a^{\frac{t}{3}} = 5

5^{x + 5} = 1

8 1^{x} = 2 7^{x + 2}

2^{2 x} = 32

1 0^{4 x} = 20