8^{x^2-x}=4^{x+1}

Lösung

8^{x^{2} - x} = 4^{x + 1}

x = 2, x = - \frac{1}{3}

Dezimale

x = 2, x = - 0.33333 \dots

Schritte zur Lösung

8^{x^{2} - x} = 4^{x + 1}

Wende Exponentenregel an

3 (x^{2} - x) = 2 (x + 1)

Löse

3 (x^{2} - x) = 2 (x + 1) : x = 2, x = - \frac{1}{3}

x = 2, x = - \frac{1}{3}

e^{2 x} = \frac{1}{8}

m e^{m x} + 2 e^{m x} = 0

(100)^{x} = 0

8 1^{x} = 9

e^{2 z - 1} = 1