5^{x+1}=7^{x-1}

Lösung

5^{x + 1} = 7^{x - 1}

x = \frac{ln ( 35 )}{ln ( 7 ) - ln ( 5 )}

Dezimale

x = 10.56654 \dots

Schritte zur Lösung

5^{x + 1} = 7^{x - 1}

Wende Exponentenregel an

(x + 1) ln (5) = (x - 1) ln (7)

Löse

(x + 1) ln (5) = (x - 1) ln (7) : x = \frac{ln ( 35 )}{ln ( 7 ) - ln ( 5 )}

x = \frac{ln ( 35 )}{ln ( 7 ) - ln ( 5 )}

9^{x} - 4 \cdot 3^{x + 1} + 27 = 0

2 x^{- 3} e^{5 l n (x)} - x - 3 = 0

5^{x - 3} = 1

5 e^{9 x - 7} = 17

6 4^{x} = \frac{1}{4}