3^{x-9}=81^{5x+1}

Lösung

3^{x - 9} = 8 1^{5 x + 1}

x = - \frac{13}{19}

Dezimale

x = - 0.68421 \dots

Schritte zur Lösung

3^{x - 9} = 8 1^{5 x + 1}

Wende Exponentenregel an

x - 9 = 4 (5 x + 1)

Löse

x - 9 = 4 (5 x + 1) : x = - \frac{13}{19}

x = - \frac{13}{19}

3^{1 - 2 x} = 243

2^{x} + 2^{x + 1} = \frac{3}{2}

3^{2 x + 1} - 26 (3^{x}) - 9 = 0

e^{x^{2} + 1} = 5 e^{- x}

x^{5} = 5^{x}