e^{7x}=3^{4x-1}

Lösung

e^{7 x} = 3^{4 x - 1}

x = - \frac{ln ( 3 )}{7 - 4 ln ( 3 )}

Dezimale

x = - 0.42164 \dots

Schritte zur Lösung

e^{7 x} = 3^{4 x - 1}

Wende Exponentenregel an

7 x = (4 x - 1) ln (3)

Löse

7 x = (4 x - 1) ln (3) : x = - \frac{ln ( 3 )}{7 - 4 ln ( 3 )}

x = - \frac{ln ( 3 )}{7 - 4 ln ( 3 )}

\frac{5 ^{x} - 5 ^{- x}}{2} = 3

2 (3^{x}) = 5

x = e^{x}

6^{1 - x} = 1 0^{x}

x^{l o g_{2} (x) + 2} = 8