What are the solutions to the equation x^2+2x=48 ?

The solutions to the equation x^2+2x=48 are x=6,x=-8

Find the zeros of x^2+2x=48

The zeros of x^2+2x=48 are x=6,x=-8

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x^{2} + 2 x = 48

x = 6, x = - 8

Solution steps

x^{2} + 2 x = 48

Move

48

to the left side

x^{2} + 2 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 48) = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 \cdot 1}, x_{2} = \frac{- 2 - 14}{2 \cdot 1}

x = \frac{- 2 + 14}{2 \cdot 1} : 6

x = \frac{- 2 - 14}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 6, x = - 8

\frac{7 ^{6}}{7 ^{- 2}}

x^{2} = 6 x - 19

10 x^{2} - 29 x - 3

49 x^{2} - 36 y^{2}

103 x - 6 = - 6 x - 103

What are the solutions to the equation x^2+2x=48 ?
The solutions to the equation x^2+2x=48 are x=6,x=-8
Find the zeros of x^2+2x=48
The zeros of x^2+2x=48 are x=6,x=-8