What is factor 4x^2-19x+12 ?

The solution to factor 4x^2-19x+12 is (4x-3)(x-4)

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factor 4x^2-19x+12

factor

4 x^{2} - 19 x + 12

(4 x - 3) (x - 4)

Solution steps

4 x^{2} - 19 x + 12

Break the expression into groups

= (4 x^{2} - 3 x) + (- 16 x + 12)

Factor out

x

from

4 x^{2} - 3 x : x (4 x - 3)

Factor out

- 4

from

- 16 x + 12 : - 4 (4 x - 3)

= x (4 x - 3) - 4 (4 x - 3)

Factor out common term

4 x - 3

= (4 x - 3) (x - 4)

y^{4} \cdot y^{6}

x^{3} - 12 x^{2} + 20 x

2 x^{2} + 3 x - 17 = 0

5 \cdot 1 0^{9}

\frac{3 ^{4}}{3 ^{2}}