What are the solutions to the equation 2x^2+3x-17=0 ?

The solutions to the equation 2x^2+3x-17=0 are x=(-3+sqrt(145))/4 ,x=(-3-sqrt(145))/4

Find the zeros of 2x^2+3x-17=0

The zeros of 2x^2+3x-17=0 are x=(-3+sqrt(145))/4 ,x=(-3-sqrt(145))/4

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2 x^{2} + 3 x - 17 = 0

x = \frac{- 3 + 145}{4}, x = \frac{- 3 - 145}{4}

Solution steps

2 x^{2} + 3 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 17 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 17) = 145

x_{1, 2} = \frac{- 3 \pm 145}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 145}{2 \cdot 2}, x_{2} = \frac{- 3 - 145}{2 \cdot 2}

x = \frac{- 3 + 145}{2 \cdot 2} : \frac{- 3 + 145}{4}

x = \frac{- 3 - 145}{2 \cdot 2} : \frac{- 3 - 145}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 145}{4}, x = \frac{- 3 - 145}{4}

5 \cdot 1 0^{9}

\frac{3 ^{4}}{3 ^{2}}

x^{2} = 2 (x - 1) (x + 2)

- 3 (4 x - 5) = - 33

11 + 7 x \geq - 17

What are the solutions to the equation 2x^2+3x-17=0 ?
The solutions to the equation 2x^2+3x-17=0 are x=(-3+sqrt(145))/4 ,x=(-3-sqrt(145))/4
Find the zeros of 2x^2+3x-17=0
The zeros of 2x^2+3x-17=0 are x=(-3+sqrt(145))/4 ,x=(-3-sqrt(145))/4