16x^2+22=0

解

16 x^{2} + 22 = 0

x = \frac{11}{2 2} i, x = - \frac{11}{2 2} i

解答ステップ

16 x^{2} + 22 = 0

22

を右側に移動します

16 x^{2} = - 22

以下で両辺を割る

16

x^{2} = - \frac{11}{8}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = - \frac{11}{8}, x = - - \frac{11}{8}

- \frac{11}{8} = \frac{11}{2 2} i

- - \frac{11}{8} = - \frac{11}{2 2} i

x = \frac{11}{2 2} i, x = - \frac{11}{2 2} i