|((x-7))/((4x-15))|>8

Lösung

\frac{( x - 7 )}{( 4 x - 15 )} > 8

\frac{113}{31} < x < \frac{15}{4} or \frac{15}{4} < x < \frac{127}{33}

Intervall-Notation

(\frac{113}{31}, \frac{15}{4}) \cup (\frac{15}{4}, \frac{127}{33})

Dezimale

3.64516 \dots < x < 3.75 or 3.75 < x < 3.84848 \dots

Schritte zur Lösung

\frac{x - 7}{4 x - 15} > 8

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

\frac{x - 7}{4 x - 15} < - 8 or \frac{x - 7}{4 x - 15} > 8

\frac{x - 7}{4 x - 15} < - 8 or \frac{x - 7}{4 x - 15} > 8

\frac{113}{31} < x < \frac{15}{4} or \frac{15}{4} < x < \frac{127}{33}

- 16 = \frac{8 x}{5}

3 n^{2} + 8 n + 16 = 2 n^{2}

2 \geq \frac{n}{4} - 2

4 x + 3 < 15

m^{2} + 2 m + 5 = 0