What are the solutions to the equation -6y-y^2=-28 ?

The solutions to the equation -6y-y^2=-28 are y=-3-sqrt(37),y=sqrt(37)-3

Find the zeros of -6y-y^2=-28

The zeros of -6y-y^2=-28 are y=-3-sqrt(37),y=sqrt(37)-3

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- 6 y - y^{2} = - 28

y = - 3 - 37, y = 37 - 3

Solution steps

- 6 y - y^{2} = - 28

Move

28

to the left side

- 6 y - y^{2} + 28 = 0

Write in the standard form

a x^{2} + b x + c = 0

- y^{2} - 6 y + 28 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 28}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 28 = 237

y_{1, 2} = \frac{- ( - 6 ) \pm 2 37}{2 ( - 1 )}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 37}{2 ( - 1 )}, y_{2} = \frac{- ( - 6 ) - 2 37}{2 ( - 1 )}

y = \frac{- ( - 6 ) + 2 37}{2 ( - 1 )} : - 3 - 37

y = \frac{- ( - 6 ) - 2 37}{2 ( - 1 )} : 37 - 3

The solutions to the quadratic equation are:

y = - 3 - 37, y = 37 - 3

14 x - 16 = 10 x

y^{2} + 9 = 0

14 = - (p - 8)

\frac{x ^{4} - 1}{x - 1}

What are the solutions to the equation -6y-y^2=-28 ?
The solutions to the equation -6y-y^2=-28 are y=-3-sqrt(37),y=sqrt(37)-3
Find the zeros of -6y-y^2=-28
The zeros of -6y-y^2=-28 are y=-3-sqrt(37),y=sqrt(37)-3