What are the solutions to the equation y^2+9=0 ?

The solutions to the equation y^2+9=0 are y=3i,y=-3i

Find the zeros of y^2+9=0

The zeros of y^2+9=0 are y=3i,y=-3i

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y^{2} + 9 = 0

y = 3 i, y = - 3 i

Solution steps

y^{2} + 9 = 0

Move

9

to the right side

y^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 9, y = - - 9

- 9 = 3 i

- - 9 = - 3 i

y = 3 i, y = - 3 i

14 = - (p - 8)

\frac{x ^{4} - 1}{x - 1}

- 9 \leq x - 1 < 0

\frac{1}{∣ x - 4 ∣} \geq \frac{1}{∣ x + 7 ∣}

What are the solutions to the equation y^2+9=0 ?
The solutions to the equation y^2+9=0 are y=3i,y=-3i
Find the zeros of y^2+9=0
The zeros of y^2+9=0 are y=3i,y=-3i