What are the solutions to the equation 0=-16t^2+32t+1584 ?

The solutions to the equation 0=-16t^2+32t+1584 are t=-9,t=11

Find the zeros of 0=-16t^2+32t+1584

The zeros of 0=-16t^2+32t+1584 are t=-9,t=11

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0 = - 16 t^{2} + 32 t + 1584

t = - 9, t = 11

Solution steps

0 = - 16 t^{2} + 32 t + 1584

Switch sides

- 16 t^{2} + 32 t + 1584 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 16 ) \cdot 1584}{2 ( - 16 )}

3 2^{2} - 4 (- 16) \cdot 1584 = 320

t_{1, 2} = \frac{- 32 \pm 320}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 32 + 320}{2 ( - 16 )}, t_{2} = \frac{- 32 - 320}{2 ( - 16 )}

t = \frac{- 32 + 320}{2 ( - 16 )} : - 9

t = \frac{- 32 - 320}{2 ( - 16 )} : 11

The solutions to the quadratic equation are:

t = - 9, t = 11

y^{2} + y - 30 = 0

(3 x)^{2} = 8 (x - 1)

64 + 9

(\frac{16}{81})^{\frac{3}{4}}

(- 8.3)^{0}

What are the solutions to the equation 0=-16t^2+32t+1584 ?
The solutions to the equation 0=-16t^2+32t+1584 are t=-9,t=11
Find the zeros of 0=-16t^2+32t+1584
The zeros of 0=-16t^2+32t+1584 are t=-9,t=11