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受欢迎的代数 >

(x-3)(x+1)=(3x+1)(2x+1)

解答

(x - 3) (x + 1) = (3 x + 1) (2 x + 1)

解答

x = - \frac{7}{10} - i \frac{31}{10}, x = - \frac{7}{10} + i \frac{31}{10}

求解步骤

(x - 3) (x + 1) = (3 x + 1) (2 x + 1)

展开

(x - 3) (x + 1) : x^{2} - 2 x - 3

展开

(3 x + 1) (2 x + 1) : 6 x^{2} + 5 x + 1

x^{2} - 2 x - 3 = 6 x^{2} + 5 x + 1

将

1

para o lado esquerdo

x^{2} - 2 x - 4 = 6 x^{2} + 5 x

将

5 x

para o lado esquerdo

x^{2} - 7 x - 4 = 6 x^{2}

将

6 x^{2}

para o lado esquerdo

- 5 x^{2} - 7 x - 4 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 5 ) ( - 4 )}{2 ( - 5 )}

化简

(- 7)^{2} - 4 (- 5) (- 4) : 31 i

x_{1, 2} = \frac{- ( - 7 ) \pm 31 i}{2 ( - 5 )}

将解分隔开

x_{1} = \frac{- ( - 7 ) + 31 i}{2 ( - 5 )}, x_{2} = \frac{- ( - 7 ) - 31 i}{2 ( - 5 )}

x = \frac{- ( - 7 ) + 31 i}{2 ( - 5 )} : - \frac{7}{10} - i \frac{31}{10}

x = \frac{- ( - 7 ) - 31 i}{2 ( - 5 )} : - \frac{7}{10} + i \frac{31}{10}

二次方程组的解是:

x = - \frac{7}{10} - i \frac{31}{10}, x = - \frac{7}{10} + i \frac{31}{10}

作图

流行的例子

solvefor h,h+s^2=h^2s

so l v e f or h, h + s^{2} = h^{2} s

solvefor x,(p-3)*x^2-2(p-3)*x+2=0

so l v e f or x, (p - 3) \cdot x^{2} - 2 (p - 3) \cdot x + 2 = 0

a = x^{2} + 16 x + 64

a^{2} + 324 = 0

25r^2+175r-168=0

25 r^{2} + 175 r - 168 = 0