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受欢迎的代数 >

solvefor h,h+s^2=h^2s

解答

求解

h, h + s^{2} = h^{2} s

解答

h = \frac{1 + 1 + 4 s ^{3}}{2 s}, h = \frac{1 - 1 + 4 s ^{3}}{2 s}; s \neq = 0

求解步骤

h + s^{2} = h^{2} s

交换两边

h^{2} s = h + s^{2}

将

s^{2}

para o lado esquerdo

h^{2} s - s^{2} = h

将

h

para o lado esquerdo

h^{2} s - s^{2} - h = 0

改写成标准形式

a x^{2} + b x + c = 0

s h^{2} - h - s^{2} = 0

使用求根公式求解

h_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 s ( - s ^{2} )}{2 s}

化简

(- 1)^{2} - 4 s (- s^{2}) : 1 + 4 s^{3}

h_{1, 2} = \frac{- ( - 1 ) \pm 1 + 4 s ^{3}}{2 s}; s \neq = 0

将解分隔开

h_{1} = \frac{- ( - 1 ) + 1 + 4 s ^{3}}{2 s}, h_{2} = \frac{- ( - 1 ) - 1 + 4 s ^{3}}{2 s}

h = \frac{- ( - 1 ) + 1 + 4 s ^{3}}{2 s} : \frac{1 + 1 + 4 s ^{3}}{2 s}

h = \frac{- ( - 1 ) - 1 + 4 s ^{3}}{2 s} : \frac{1 - 1 + 4 s ^{3}}{2 s}

二次方程组的解是:

h = \frac{1 + 1 + 4 s ^{3}}{2 s}, h = \frac{1 - 1 + 4 s ^{3}}{2 s}; s \neq = 0

作图

流行的例子

solvefor x,(p-3)*x^2-2(p-3)*x+2=0

so l v e f or x, (p - 3) \cdot x^{2} - 2 (p - 3) \cdot x + 2 = 0

a = x^{2} + 16 x + 64

a^{2} + 324 = 0

25r^2+175r-168=0

25 r^{2} + 175 r - 168 = 0

10r^2-(10+2(10r-10))=2.5

10 r^{2} - (10 + 2 (10 r - 10)) = 2.5