What are the solutions to the equation x^2+4^2=5^2 ?

The solutions to the equation x^2+4^2=5^2 are x=3,x=-3

Find the zeros of x^2+4^2=5^2

The zeros of x^2+4^2=5^2 are x=3,x=-3

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x^{2} + 4^{2} = 5^{2}

x = 3, x = - 3

Solution steps

x^{2} + 4^{2} = 5^{2}

Move

4^{2}

to the right side

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

5 + 3 x \geq 4 - x

169 a^{4} - 1

x^{2} - 16 x + 50 = 0

\frac{1}{x} + \frac{1}{x - 1} \geq 0

7 \leq 5

What are the solutions to the equation x^2+4^2=5^2 ?
The solutions to the equation x^2+4^2=5^2 are x=3,x=-3
Find the zeros of x^2+4^2=5^2
The zeros of x^2+4^2=5^2 are x=3,x=-3