What are the solutions to the equation x^2-16x+50=0 ?

The solutions to the equation x^2-16x+50=0 are x=8+sqrt(14),x=8-sqrt(14)

Find the zeros of x^2-16x+50=0

The zeros of x^2-16x+50=0 are x=8+sqrt(14),x=8-sqrt(14)

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x^{2} - 16 x + 50 = 0

x = 8 + 14, x = 8 - 14

Solution steps

x^{2} - 16 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 50 = 214

x_{1, 2} = \frac{- ( - 16 ) \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 14}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 14}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 14}{2 \cdot 1} : 8 + 14

x = \frac{- ( - 16 ) - 2 14}{2 \cdot 1} : 8 - 14

The solutions to the quadratic equation are:

x = 8 + 14, x = 8 - 14

\frac{1}{x} + \frac{1}{x - 1} \geq 0

7 \leq 5

4 x - 4 = 2 x - 1

(x + i 2)^{2} (x - i 2)^{2}

- 0.72 b = 0.504

What are the solutions to the equation x^2-16x+50=0 ?
The solutions to the equation x^2-16x+50=0 are x=8+sqrt(14),x=8-sqrt(14)
Find the zeros of x^2-16x+50=0
The zeros of x^2-16x+50=0 are x=8+sqrt(14),x=8-sqrt(14)