What is the answer to |7x-1|+9=19 ?

The answer to |7x-1|+9=19 is x=-9/7 \lor x= 11/7

Solve for x: |7x-1|+9=19

The solution is x=-9/7 \lor x= 11/7

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∣ 7 x - 1 ∣ + 9 = 19

x = - \frac{9}{7} or x = \frac{11}{7}

Solution steps

∣ 7 x - 1 ∣ + 9 = 19

Move

9

to the right side

∣ 7 x - 1 ∣ = 10

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

7 x - 1 = - 10 or 7 x - 1 = 10

7 x - 1 = - 10 or 7 x - 1 = 10

x = - \frac{9}{7} or x = \frac{11}{7}

2 x^{2} + 9 = 0

- 6 a + 33 \leq 9

\frac{4}{3} π 2^{3}

(8^{5})^{3}

(x^{- 2})^{- 2}

What is the answer to |7x-1|+9=19 ?
The answer to |7x-1|+9=19 is x=-9/7 \lor x= 11/7
Solve for x: |7x-1|+9=19
The solution is x=-9/7 \lor x= 11/7