What are the solutions to the equation 2x^2+9=0 ?

The solutions to the equation 2x^2+9=0 are x= 3/(sqrt(2))i,x=-3/(sqrt(2))i

Find the zeros of 2x^2+9=0

The zeros of 2x^2+9=0 are x= 3/(sqrt(2))i,x=-3/(sqrt(2))i

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2 x^{2} + 9 = 0

x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

2 x^{2} + 9 = 0

Move

9

to the right side

2 x^{2} = - 9

Divide both sides by

2

x^{2} = - \frac{9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{9}{2}, x = - - \frac{9}{2}

- \frac{9}{2} = \frac{3}{2} i

- - \frac{9}{2} = - \frac{3}{2} i

x = \frac{3}{2} i, x = - \frac{3}{2} i

- 6 a + 33 \leq 9

\frac{4}{3} π 2^{3}

(8^{5})^{3}

(x^{- 2})^{- 2}

6 x^{2} + 19 x + 3

What are the solutions to the equation 2x^2+9=0 ?
The solutions to the equation 2x^2+9=0 are x= 3/(sqrt(2))i,x=-3/(sqrt(2))i
Find the zeros of 2x^2+9=0
The zeros of 2x^2+9=0 are x= 3/(sqrt(2))i,x=-3/(sqrt(2))i