x^3+2x^2>8x

Lösung

x^{3} + 2 x^{2} > 8 x

- 4 < x < 0 or x > 2

Intervall-Notation

(- 4, 0) \cup (2, \infty)

Schritte zur Lösung

x^{3} + 2 x^{2} > 8 x

Rewrite in standard form

x^{3} + 2 x^{2} - 8 x > 0

Faktorisiere

x^{3} + 2 x^{2} - 8 x : x (x - 2) (x + 4)

x (x - 2) (x + 4) > 0

Identifiziere die Intervalle

- 4 < x < 0 or x > 2

- 3 + x = 7

∣ t + 2 ∣ = 2

x^{2} - 10 x \geq - 24

4 x^{2} + x - \frac{1}{8} = 0

r + 5 \leq 11