|t+2|=2

Lösung

∣ t + 2 ∣ = 2

t = - 4 or t = 0

Schritte zur Lösung

∣ t + 2 ∣ = 2

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

t + 2 = - 2 or t + 2 = 2

t + 2 = - 2 or t + 2 = 2

t = - 4 or t = 0

x^{2} - 10 x \geq - 24

4 x^{2} + x - \frac{1}{8} = 0

r + 5 \leq 11

4 x^{2} - 8 = 32

s im pl i f y \frac{25 x y ^{2}}{125 x ^{5} y ^{7}}