What are the solutions to the equation (x+6)(2x-1)=0 ?

The solutions to the equation (x+6)(2x-1)=0 are x=-6,x= 1/2

Find the zeros of (x+6)(2x-1)=0

The zeros of (x+6)(2x-1)=0 are x=-6,x= 1/2

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(x + 6) (2 x - 1) = 0

x = - 6, x = \frac{1}{2}

Solution steps

(x + 6) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or 2 x - 1 = 0

Solve

x + 6 = 0 : x = - 6

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = - 6, x = \frac{1}{2}

0 = (x - 2)^{2}

∣ x - 3 ∣ < 4

7 - (- 3) + (4 + 3)

\frac{65}{100} \cdot x + \frac{20}{100} \cdot 8 = \frac{85}{100} \cdot 8 + x

4 ∣ y + 4 ∣ - 8 = 0

What are the solutions to the equation (x+6)(2x-1)=0 ?
The solutions to the equation (x+6)(2x-1)=0 are x=-6,x= 1/2
Find the zeros of (x+6)(2x-1)=0
The zeros of (x+6)(2x-1)=0 are x=-6,x= 1/2