What are the solutions to the equation 0=(x-2)^2 ?

The solutions to the equation 0=(x-2)^2 are x=2

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0=(x-2)^2

0 = (x - 2)^{2}

x = 2

Solution steps

0 = (x - 2)^{2}

Switch sides

(x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x - 2 = 0 : x = 2

The solution to the quadratic equation is:

x = 2

∣ x - 3 ∣ < 4

7 - (- 3) + (4 + 3)

\frac{65}{100} \cdot x + \frac{20}{100} \cdot 8 = \frac{85}{100} \cdot 8 + x

4 ∣ y + 4 ∣ - 8 = 0

1 + t^{2} + \frac{1}{4} t^{4}

What are the solutions to the equation 0=(x-2)^2 ?
The solutions to the equation 0=(x-2)^2 are x=2
Find the zeros of 0=(x-2)^2
The zeros of 0=(x-2)^2 are x=2