What are the solutions to the equation (2x-15)(5x+16)=0 ?

The solutions to the equation (2x-15)(5x+16)=0 are x= 15/2 ,x=-16/5

Find the zeros of (2x-15)(5x+16)=0

The zeros of (2x-15)(5x+16)=0 are x= 15/2 ,x=-16/5

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(2 x - 15) (5 x + 16) = 0

x = \frac{15}{2}, x = - \frac{16}{5}

Solution steps

(2 x - 15) (5 x + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 15 = 0 or 5 x + 16 = 0

Solve

2 x - 15 = 0 : x = \frac{15}{2}

Solve

5 x + 16 = 0 : x = - \frac{16}{5}

The solutions to the quadratic equation are:

x = \frac{15}{2}, x = - \frac{16}{5}

\frac{w}{6} + \frac{w}{8} = \frac{7}{6}

36 a^{2} - 49 b^{2}

- 3 x + 1 > 13

15 k^{10} + 15 k^{9} + 15 k^{7} - 30 k^{5}

3 x^{2} + 45 = 24 x

What are the solutions to the equation (2x-15)(5x+16)=0 ?
The solutions to the equation (2x-15)(5x+16)=0 are x= 15/2 ,x=-16/5
Find the zeros of (2x-15)(5x+16)=0
The zeros of (2x-15)(5x+16)=0 are x= 15/2 ,x=-16/5