What are the solutions to the equation 3x^2+45=24x ?

The solutions to the equation 3x^2+45=24x are x=5,x=3

Find the zeros of 3x^2+45=24x

The zeros of 3x^2+45=24x are x=5,x=3

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3 x^{2} + 45 = 24 x

x = 5, x = 3

Solution steps

3 x^{2} + 45 = 24 x

Move

24 x

to the left side

3 x^{2} + 45 - 24 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 24 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 45}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 \cdot 45 = 6

x_{1, 2} = \frac{- ( - 24 ) \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 6}{2 \cdot 3}

x = \frac{- ( - 24 ) + 6}{2 \cdot 3} : 5

x = \frac{- ( - 24 ) - 6}{2 \cdot 3} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

(- 27 x^{- 9})^{\frac{1}{3}}

16 (x + 2) - 8 = 16 x + 24

2 \cdot 2

\frac{4}{7} x - 4 > 12

- (4)^{0}

What are the solutions to the equation 3x^2+45=24x ?
The solutions to the equation 3x^2+45=24x are x=5,x=3
Find the zeros of 3x^2+45=24x
The zeros of 3x^2+45=24x are x=5,x=3