erweitern (d^2)/(d^2x)(x^3+y^3=1)

Lösung

erweitern

\frac{d ^{2}}{d ^{2} x} (x^{3} + y^{3} = 1)

x^{2} + \frac{y ^{3}}{x} = 1

Schritte zur Lösung

\frac{d ^{2}}{d ^{2} x} (x^{3} + y^{3} = 1)

= \frac{d ^{2}}{d ^{2} x} (x^{3} + 1 = y^{3})

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = \frac{d ^{2}}{d ^{2} x}, b = x^{3}, c = y^{3} = 1

\frac{d ^{2}}{d ^{2} x} x^{3} + \frac{d ^{2}}{d ^{2} x} y^{3} = 1

Multipliziere aus

\frac{d ^{2}}{d ^{2} x} x^{3} + \frac{d ^{2}}{d ^{2} x} y^{3} : x^{2} + \frac{y ^{3}}{x}

x^{2} + \frac{y ^{3}}{x} = 1

e x p an d (0, - 5) (x - 1)

e x p an d \frac{s ^{2} + s - 10 + e ^{- s}}{( s - 1 ) ( s - 2 ) ( s + 4 )}

s im pl i f y (3 + 36) (3 - 36)

e x p an d 24 e^{- 20 t} + 20 (\frac{6}{5} - \frac{6}{5} e^{- 20 t})

\frac{\partial}{\partial u} ((x) (u^{4} + v w))